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How to Balance Chemical Equations

Examples of balancing three sample chemical equations for all levels of chemistry. TRANSCRIPT: So I have 3 chemical equations here that I need to balance today. The first one is blank N2 + blank H2 yields blank NH3. The first thing that we need to do is make sure that the amounts of the elements on one side of the reaction are the same as the amount on the other side. I’m just going to set up a list to organize myself, and I can see that the only elements here are just N and H. On the left side, we have 2 Ns, and we also have 2 Hs, and then on the right side, I have 1 N and 3 Hs. Let’s see what happens when we put a 2 here. That means we’re going to multiply this whole thing by 2. So instead of 1 N, we’ll have 2 Ns, and instead of 3 Hs, we’ll multiply that by 2 to get 6 Hs. Now the Ns are good, so we can leave this as 1, and now we need to change this to make the left side have 6 Hs instead of just 2. What we can do is put a 3 here, so instead of 2 we’ll have 6 hydrogens. Now we have the same number of nitrogens and the same number of hydrogens. So we’re done. Next one’s a little bit harder. I can see we have the same number of sodiums, so I’m going to leave that alone. The next element we have is Br, so Br is 1 over here but 2 over here so obviously we need to put a 2 in front. So now we have 2 sodiums, 1 sodium, 2 Brs, 2 Brs. Since we only have 1 Na, we need to multiply that by 2, so 2 of these, two of these. Next one, Ca, calcium. We have 1 calcium, 1 calcium. We’re good. Next one, F, two Fs, two Fs. And we’re good. Last one. 2 Hs, looking on the right side we have 1 H. So let’s put a 2. We’re done with the Hs. Now sulfur. We have 1 sulfur over here, so that’s good. Oxygen. Now remember, don’t forget about the other compounds on the left side of the equation. So we have 4 plus 2, which means we have 6 Os in total. Over here we have 2 times 2 is 4, so 4 oxygens, and here we have another 4, so that’s going to be 8 Os. Let’s leave that alone right now and let’s move onto something else because we have both of these compounds with an O in it, and both of these compounds with an O in it, so we’ll just leave it alone for now, because it’ll get too complicated. And I see over here we have 2 Nas and 1 Na on the left side. So let’s multiply that by 2 to balance out the sodiums. Now we have 2 nitrogens because 2 times all of this will give you 2 nitrogens and we have 2 nitrogens so the nitrogens balance out. Basically, all of the elements are balanced out except for oxygen. And since we multiplied this whole thing by 2, instead of 6 oxygens, we have 4 + 4 so that’s going to be 8 oxygens. And it looks like we’re done.